Base | Representation |
---|---|
bin | 1011111100000110101111… |
… | …0010000110001010011010 |
3 | 1201110221200010002102102110 |
4 | 2333001223302012022122 |
5 | 3210034030424214010 |
6 | 43530322045413150 |
7 | 2523260645630655 |
oct | 277015362061232 |
9 | 51427603072373 |
10 | 13127228351130 |
11 | 42012541a6023 |
12 | 158018a26a1b6 |
13 | 742b7a57b31a |
14 | 33550b36a89c |
15 | 17b709011120 |
hex | bf06bc8629a |
13127228351130 has 16 divisors (see below), whose sum is σ = 31505348042784. Its totient is φ = 3500594226960.
The previous prime is 13127228351101. The next prime is 13127228351143. The reversal of 13127228351130 is 3115382272131.
13127228351130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131272283511302 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218787139156 + ... + 218787139215.
It is an arithmetic number, because the mean of its divisors is an integer number (1969084252674).
Almost surely, 213127228351130 is an apocalyptic number.
13127228351130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13127228351130 is an abundant number, since it is smaller than the sum of its proper divisors (18378119691654).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13127228351130 is a wasteful number, since it uses less digits than its factorization.
13127228351130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437574278381.
The product of its (nonzero) digits is 60480, while the sum is 39.
The spelling of 13127228351130 in words is "thirteen trillion, one hundred twenty-seven billion, two hundred twenty-eight million, three hundred fifty-one thousand, one hundred thirty".
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