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13127229813857 is a prime number
BaseRepresentation
bin1011111100000110101111…
…0111101011010001100001
31201110221200012211201220112
42333001223313223101201
53210034031313020412
643530322141021105
72523260664232325
oct277015367532141
951427605751815
1013127229813857
114201255004a95
12158018a854795
13742b7a971043
1433550b62b985
1517b7091ee722
hexbf06bdeb461

13127229813857 has 2 divisors, whose sum is σ = 13127229813858. Its totient is φ = 13127229813856.

The previous prime is 13127229813773. The next prime is 13127229813869. The reversal of 13127229813857 is 75831892272131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7947217684561 + 5180012129296 = 2819081^2 + 2275964^2 .

It is a cyclic number.

It is not a de Polignac number, because 13127229813857 - 210 = 13127229812833 is a prime.

It is a super-3 number, since 3×131272298138573 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13127229813796 and 13127229813805.

It is not a weakly prime, because it can be changed into another prime (13127229812857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563614906928 + 6563614906929.

It is an arithmetic number, because the mean of its divisors is an integer number (6563614906929).

Almost surely, 213127229813857 is an apocalyptic number.

It is an amenable number.

13127229813857 is a deficient number, since it is larger than the sum of its proper divisors (1).

13127229813857 is an equidigital number, since it uses as much as digits as its factorization.

13127229813857 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10160640, while the sum is 59.

The spelling of 13127229813857 in words is "thirteen trillion, one hundred twenty-seven billion, two hundred twenty-nine million, eight hundred thirteen thousand, eight hundred fifty-seven".