Base | Representation |
---|---|
bin | 10011000110100100110… |
… | …110100111011111100001 |
3 | 11122111101110121102021102 |
4 | 103012210312213133201 |
5 | 133001433041244431 |
6 | 2443021001004145 |
7 | 163561456513511 |
oct | 23064466473741 |
9 | 4574343542242 |
10 | 1312730806241 |
11 | 4667a9354368 |
12 | 1924baa83655 |
13 | 96a3679629a |
14 | 4777227d841 |
15 | 24231900dcb |
hex | 131a4da77e1 |
1312730806241 has 2 divisors, whose sum is σ = 1312730806242. Its totient is φ = 1312730806240.
The previous prime is 1312730806229. The next prime is 1312730806381. The reversal of 1312730806241 is 1426080372131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1194998785600 + 117732020641 = 1093160^2 + 343121^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312730806241 - 226 = 1312663697377 is a prime.
It is a super-4 number, since 4×13127308062414 (a number of 50 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312730806195 and 1312730806204.
It is not a weakly prime, because it can be changed into another prime (1312730806201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656365403120 + 656365403121.
It is an arithmetic number, because the mean of its divisors is an integer number (656365403121).
Almost surely, 21312730806241 is an apocalyptic number.
It is an amenable number.
1312730806241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312730806241 is an equidigital number, since it uses as much as digits as its factorization.
1312730806241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 38.
The spelling of 1312730806241 in words is "one trillion, three hundred twelve billion, seven hundred thirty million, eight hundred six thousand, two hundred forty-one".
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