Base | Representation |
---|---|
bin | 1011111100000111011100… |
… | …1101100110101000101011 |
3 | 1201110222011110220212001210 |
4 | 2333001313031212220223 |
5 | 3210034424022031103 |
6 | 43530353055444203 |
7 | 2523265464566553 |
oct | 277016715465053 |
9 | 51428143825053 |
10 | 13127420111403 |
11 | 4201342470394 |
12 | 1580222526663 |
13 | 742bab20c040 |
14 | 335528a06163 |
15 | 17b71ac8de03 |
hex | bf077366a2b |
13127420111403 has 32 divisors (see below), whose sum is σ = 18898511924992. Its totient is φ = 8057465539200.
The previous prime is 13127420111401. The next prime is 13127420111419. The reversal of 13127420111403 is 30411102472131.
It is not a de Polignac number, because 13127420111403 - 21 = 13127420111401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13127420111401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 302376768 + ... + 302420178.
It is an arithmetic number, because the mean of its divisors is an integer number (590578497656).
Almost surely, 213127420111403 is an apocalyptic number.
13127420111403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13127420111403 is a deficient number, since it is larger than the sum of its proper divisors (5771091813589).
13127420111403 is a wasteful number, since it uses less digits than its factorization.
13127420111403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63355.
The product of its (nonzero) digits is 4032, while the sum is 30.
Adding to 13127420111403 its reverse (30411102472131), we get a palindrome (43538522583534).
The spelling of 13127420111403 in words is "thirteen trillion, one hundred twenty-seven billion, four hundred twenty million, one hundred eleven thousand, four hundred three".
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