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13127489760523 is a prime number
BaseRepresentation
bin1011111100000111101101…
…0111010010110100001011
31201110222100022222101200211
42333001323113102310023
53210040044334314043
643530404024341551
72523300301602325
oct277017327226413
951428308871624
1013127489760523
114201378811846
1215802419148b7
13742bbc786c38
14335533d76615
1517b721e4aa9d
hexbf07b5d2d0b

13127489760523 has 2 divisors, whose sum is σ = 13127489760524. Its totient is φ = 13127489760522.

The previous prime is 13127489760481. The next prime is 13127489760557. The reversal of 13127489760523 is 32506798472131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13127489760523 - 217 = 13127489629451 is a prime.

It is not a weakly prime, because it can be changed into another prime (13127489760023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563744880261 + 6563744880262.

It is an arithmetic number, because the mean of its divisors is an integer number (6563744880262).

It is a 1-persistent number, because it is pandigital, but 2⋅13127489760523 = 26254979521046 is not.

Almost surely, 213127489760523 is an apocalyptic number.

13127489760523 is a deficient number, since it is larger than the sum of its proper divisors (1).

13127489760523 is an equidigital number, since it uses as much as digits as its factorization.

13127489760523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 58.

The spelling of 13127489760523 in words is "thirteen trillion, one hundred twenty-seven billion, four hundred eighty-nine million, seven hundred sixty thousand, five hundred twenty-three".