Base | Representation |
---|---|
bin | 1011111100000111101101… |
… | …0111010010101100010111 |
3 | 1201110222100022222101000022 |
4 | 2333001323113102230113 |
5 | 3210040044334310043 |
6 | 43530404024335355 |
7 | 2523300301601012 |
oct | 277017327225427 |
9 | 51428308871008 |
10 | 13127489760023 |
11 | 4201378811431 |
12 | 158024191455b |
13 | 742bbc786942 |
14 | 335533d76379 |
15 | 17b721e4a868 |
hex | bf07b5d2b17 |
13127489760023 has 2 divisors, whose sum is σ = 13127489760024. Its totient is φ = 13127489760022.
The previous prime is 13127489759999. The next prime is 13127489760059. The reversal of 13127489760023 is 32006798472131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13127489760023 - 224 = 13127472982807 is a prime.
It is a super-3 number, since 3×131274897600233 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13127489760523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563744880011 + 6563744880012.
It is an arithmetic number, because the mean of its divisors is an integer number (6563744880012).
Almost surely, 213127489760023 is an apocalyptic number.
13127489760023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13127489760023 is an equidigital number, since it uses as much as digits as its factorization.
13127489760023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 53.
The spelling of 13127489760023 in words is "thirteen trillion, one hundred twenty-seven billion, four hundred eighty-nine million, seven hundred sixty thousand, twenty-three".
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