1312793897 has 2 divisors, whose sum is σ = 1312793898. Its totient is φ = 1312793896.

The previous prime is 1312793893. The next prime is 1312793899. The reversal of 1312793897 is 7983972131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 739622416 + 573171481 = 27196^2 + 23941^2 .

It is an emirp because it is prime and its reverse (7983972131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312793897 - 2² = 1312793893 is a prime.

Together with 1312793899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1312793893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656396948 + 656396949.

It is an arithmetic number, because the mean of its divisors is an integer number (656396949).

Almost surely, 2^1312793897 is an apocalyptic number.

It is an amenable number.

1312793897 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312793897 is an equidigital number, since it uses as much as digits as its factorization.

1312793897 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 571536, while the sum is 50.

The square root of 1312793897 is about 36232.4978023873. The cubic root of 1312793897 is about 1094.9615012562.

The spelling of 1312793897 in words is "one billion, three hundred twelve million, seven hundred ninety-three thousand, eight hundred ninety-seven".