Base | Representation |
---|---|
bin | 1011111100001001111101… |
… | …1101101110100101110101 |
3 | 1201111000220112122102211002 |
4 | 2333002133131232211311 |
5 | 3210042314412130213 |
6 | 43530544102053045 |
7 | 2523321304641524 |
oct | 277023735564565 |
9 | 51430815572732 |
10 | 13128095426933 |
11 | 420165968a9a3 |
12 | 158039071a185 |
13 | 742c880b7a26 |
14 | 3355905964bb |
15 | 17b75a1d7658 |
hex | bf09f76e975 |
13128095426933 has 2 divisors, whose sum is σ = 13128095426934. Its totient is φ = 13128095426932.
The previous prime is 13128095426921. The next prime is 13128095426983. The reversal of 13128095426933 is 33962459082131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9961895125009 + 3166200301924 = 3156247^2 + 1779382^2 .
It is a cyclic number.
It is not a de Polignac number, because 13128095426933 - 222 = 13128091232629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13128095426903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6564047713466 + 6564047713467.
It is an arithmetic number, because the mean of its divisors is an integer number (6564047713467).
Almost surely, 213128095426933 is an apocalyptic number.
It is an amenable number.
13128095426933 is a deficient number, since it is larger than the sum of its proper divisors (1).
13128095426933 is an equidigital number, since it uses as much as digits as its factorization.
13128095426933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8398080, while the sum is 56.
The spelling of 13128095426933 in words is "thirteen trillion, one hundred twenty-eight billion, ninety-five million, four hundred twenty-six thousand, nine hundred thirty-three".
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