Base | Representation |
---|---|
bin | 1011111100010001000100… |
… | …1111100100111100101111 |
3 | 1201111012211120120020220001 |
4 | 2333010101033210330233 |
5 | 3210110222101220142 |
6 | 43531501332205131 |
7 | 2523416514160546 |
oct | 277042117447457 |
9 | 51435746506801 |
10 | 13130004320047 |
11 | 420244915a60a |
12 | 1580823a697a7 |
13 | 743200713394 |
14 | 3356d1cd715d |
15 | 17b81caa05b7 |
hex | bf1113e4f2f |
13130004320047 has 2 divisors, whose sum is σ = 13130004320048. Its totient is φ = 13130004320046.
The previous prime is 13130004320029. The next prime is 13130004320071. The reversal of 13130004320047 is 74002340003131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13130004320047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13130004319997 and 13130004320024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130004323047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565002160023 + 6565002160024.
It is an arithmetic number, because the mean of its divisors is an integer number (6565002160024).
Almost surely, 213130004320047 is an apocalyptic number.
13130004320047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130004320047 is an equidigital number, since it uses as much as digits as its factorization.
13130004320047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 13130004320047 its reverse (74002340003131), we get a palindrome (87132344323178).
The spelling of 13130004320047 in words is "thirteen trillion, one hundred thirty billion, four million, three hundred twenty thousand, forty-seven".
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