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1313001231023 is a prime number
BaseRepresentation
bin10011000110110100111…
…110001101001010101111
311122112002022110102100002
4103012310332031022233
5133003011303343043
62443103501054515
7163601252214116
oct23066476151257
94575068412302
101313001231023
11466927a68519
1219257555743b
1396a7a80a551
144779a154c7d
152424a51bbb8
hex131b4f8d2af

1313001231023 has 2 divisors, whose sum is σ = 1313001231024. Its totient is φ = 1313001231022.

The previous prime is 1313001231011. The next prime is 1313001231067. The reversal of 1313001231023 is 3201321003131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1313001231023 - 234 = 1295821361839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313001230986 and 1313001231004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313001239023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656500615511 + 656500615512.

It is an arithmetic number, because the mean of its divisors is an integer number (656500615512).

Almost surely, 21313001231023 is an apocalyptic number.

1313001231023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313001231023 is an equidigital number, since it uses as much as digits as its factorization.

1313001231023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1313001231023 its reverse (3201321003131), we get a palindrome (4514322234154).

The spelling of 1313001231023 in words is "one trillion, three hundred thirteen billion, one million, two hundred thirty-one thousand, twenty-three".