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1313002131310 = 25131300213131
BaseRepresentation
bin10011000110110101000…
…001101000111101101110
311122112002101011011022001
4103012311001220331232
5133003012021200220
62443103532242514
7163601262653632
oct23066501507556
94575071134261
101313002131310
11466928522961
1219257591043a
1396a7aa6426c
144779a30adc2
152424a64880a
hex131b5068f6e

1313002131310 has 8 divisors (see below), whose sum is σ = 2363403836376. Its totient is φ = 525200852520.

The previous prime is 1313002131281. The next prime is 1313002131373. The reversal of 1313002131310 is 131312003131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13130021313102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65650106556 + ... + 65650106575.

It is an arithmetic number, because the mean of its divisors is an integer number (295425479547).

Almost surely, 21313002131310 is an apocalyptic number.

1313002131310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1313002131310 is a deficient number, since it is larger than the sum of its proper divisors (1050401705066).

1313002131310 is a wasteful number, since it uses less digits than its factorization.

1313002131310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131300213138.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1313002131310 its reverse (131312003131), we get a palindrome (1444314134441).

The spelling of 1313002131310 in words is "one trillion, three hundred thirteen billion, two million, one hundred thirty-one thousand, three hundred ten".

Divisors: 1 2 5 10 131300213131 262600426262 656501065655 1313002131310