Base | Representation |
---|---|
bin | 10011000110110101000… |
… | …001111110111011001011 |
3 | 11122112002101022201200111 |
4 | 103012311001332323023 |
5 | 133003012032040014 |
6 | 2443103534215151 |
7 | 163601263510111 |
oct | 23066501767313 |
9 | 4575071281614 |
10 | 1313002221259 |
11 | 4669285844a3 |
12 | 1925759544b7 |
13 | 96a7aa961a1 |
14 | 4779a331ab1 |
15 | 2424a6652c4 |
hex | 131b507eecb |
1313002221259 has 2 divisors, whose sum is σ = 1313002221260. Its totient is φ = 1313002221258.
The previous prime is 1313002221241. The next prime is 1313002221317. The reversal of 1313002221259 is 9521222003131.
It is a weak prime.
It is an emirp because it is prime and its reverse (9521222003131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313002221259 - 217 = 1313002090187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1313002221259.
It is not a weakly prime, because it can be changed into another prime (1313002221959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656501110629 + 656501110630.
It is an arithmetic number, because the mean of its divisors is an integer number (656501110630).
Almost surely, 21313002221259 is an apocalyptic number.
1313002221259 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313002221259 is an equidigital number, since it uses as much as digits as its factorization.
1313002221259 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 1313002221259 in words is "one trillion, three hundred thirteen billion, two million, two hundred twenty-one thousand, two hundred fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •