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13130024024203 is a prime number
BaseRepresentation
bin1011111100010001001001…
…1010101111100010001011
31201111012212221122022220121
42333010102122233202023
53210110242122233303
643531503314404111
72523420143515222
oct277042232574213
951435787568817
1013130024024203
114202459298639
12158082a590637
13743204821c48
143356d4785cb9
1517b81e6939bd
hexbf1126af88b

13130024024203 has 2 divisors, whose sum is σ = 13130024024204. Its totient is φ = 13130024024202.

The previous prime is 13130024024167. The next prime is 13130024024267. The reversal of 13130024024203 is 30242042003131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13130024024203 - 217 = 13130023893131 is a prime.

It is a super-2 number, since 2×131300240242032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13130027024203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565012012101 + 6565012012102.

It is an arithmetic number, because the mean of its divisors is an integer number (6565012012102).

Almost surely, 213130024024203 is an apocalyptic number.

13130024024203 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130024024203 is an equidigital number, since it uses as much as digits as its factorization.

13130024024203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13130024024203 its reverse (30242042003131), we get a palindrome (43372066027334).

The spelling of 13130024024203 in words is "thirteen trillion, one hundred thirty billion, twenty-four million, twenty-four thousand, two hundred three".