Search a number
-
+
131300240242439 = 457661286894099
BaseRepresentation
bin11101110110101010111000…
…001011011011011100000111
3122012220011212111102022200002
4131312222320023123130013
5114202210343000224224
61143130255254511515
736441062232335342
oct3566527013333407
9565804774368602
10131300240242439
1138922134699094
1212886a4896559b
1358357373868c8
14245cd73603459
15102a6496269ae
hex776ab82db707

131300240242439 has 4 divisors (see below), whose sum is σ = 131300527594200. Its totient is φ = 131299952890680.

The previous prime is 131300240242417. The next prime is 131300240242597. The reversal of 131300240242439 is 934242042003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131300240242439 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131300240241439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142989389 + ... + 143904710.

It is an arithmetic number, because the mean of its divisors is an integer number (32825131898550).

Almost surely, 2131300240242439 is an apocalyptic number.

131300240242439 is a deficient number, since it is larger than the sum of its proper divisors (287351761).

131300240242439 is an equidigital number, since it uses as much as digits as its factorization.

131300240242439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287351760.

The product of its (nonzero) digits is 124416, while the sum is 38.

The spelling of 131300240242439 in words is "one hundred thirty-one trillion, three hundred billion, two hundred forty million, two hundred forty-two thousand, four hundred thirty-nine".

Divisors: 1 457661 286894099 131300240242439