Search a number
-
+
131300240242597 is a prime number
BaseRepresentation
bin11101110110101010111000…
…001011011011011110100101
3122012220011212111102022212221
4131312222320023123132211
5114202210343000230342
61143130255254512341
736441062232335656
oct3566527013333645
9565804774368787
10131300240242597
1138922134699218
1212886a489656b1
1358357373869ba
14245cd7360352d
15102a649626a67
hex776ab82db7a5

131300240242597 has 2 divisors, whose sum is σ = 131300240242598. Its totient is φ = 131300240242596.

The previous prime is 131300240242417. The next prime is 131300240242601. The reversal of 131300240242597 is 795242042003131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121574131436356 + 9726108806241 = 11026066^2 + 3118671^2 .

It is a cyclic number.

It is not a de Polignac number, because 131300240242597 - 211 = 131300240240549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131300240242097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650120121298 + 65650120121299.

It is an arithmetic number, because the mean of its divisors is an integer number (65650120121299).

Almost surely, 2131300240242597 is an apocalyptic number.

It is an amenable number.

131300240242597 is a deficient number, since it is larger than the sum of its proper divisors (1).

131300240242597 is an equidigital number, since it uses as much as digits as its factorization.

131300240242597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 43.

The spelling of 131300240242597 in words is "one hundred thirty-one trillion, three hundred billion, two hundred forty million, two hundred forty-two thousand, five hundred ninety-seven".