131301131030000 has 200 divisors, whose sum is σ = 318371231794176. Its totient is φ = 52441535200000.

The previous prime is 131301131029987. The next prime is 131301131030021. The reversal of 131301131030000 is 30131103131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 29902327805 + ... + 29902332195.

Almost surely, 2^{131301131030000} is an apocalyptic number.

131301131030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131301131030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159185615897088).

131301131030000 is an abundant number, since it is smaller than the sum of its proper divisors (187070100764176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131301131030000 is a wasteful number, since it uses less digits than its factorization.

131301131030000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8233 (or 8212 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 131301131030000 its reverse (30131103131), we get a palindrome (131331262133131).

The spelling of 131301131030000 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-one million, thirty thousand".