Base | Representation |
---|---|
bin | 10011000110110101101… |
… | …000000110010100110111 |
3 | 11122112010002010100211201 |
4 | 103012311220012110313 |
5 | 133003022111304142 |
6 | 2443104532313331 |
7 | 163601444443513 |
oct | 23066550062467 |
9 | 4575102110751 |
10 | 1313012213047 |
11 | 466933189477 |
12 | 192579172847 |
13 | 96a7cb840a2 |
14 | 4779b7b3143 |
15 | 2424b48aab7 |
hex | 131b5a06537 |
1313012213047 has 2 divisors, whose sum is σ = 1313012213048. Its totient is φ = 1313012213046.
The previous prime is 1313012213011. The next prime is 1313012213059. The reversal of 1313012213047 is 7403122103131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313012213047 is a prime.
It is a super-2 number, since 2×13130122130472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313012213077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656506106523 + 656506106524.
It is an arithmetic number, because the mean of its divisors is an integer number (656506106524).
Almost surely, 21313012213047 is an apocalyptic number.
1313012213047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313012213047 is an equidigital number, since it uses as much as digits as its factorization.
1313012213047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 1313012213047 its reverse (7403122103131), we get a palindrome (8716134316178).
The spelling of 1313012213047 in words is "one trillion, three hundred thirteen billion, twelve million, two hundred thirteen thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.062 sec. • engine limits •