Base | Representation |
---|---|
bin | 10011000110110101101… |
… | …000111001001100011111 |
3 | 11122112010002111221122202 |
4 | 103012311220321030133 |
5 | 133003022134441112 |
6 | 2443104541002115 |
7 | 163601446302131 |
oct | 23066550711437 |
9 | 4575102457582 |
10 | 1313012421407 |
11 | 466933310a75 |
12 | 19257925333b |
13 | 96a7cc27b8b |
14 | 4779b829051 |
15 | 2424b4cc6c2 |
hex | 131b5a3931f |
1313012421407 has 2 divisors, whose sum is σ = 1313012421408. Its totient is φ = 1313012421406.
The previous prime is 1313012421337. The next prime is 1313012421467. The reversal of 1313012421407 is 7041242103131.
It is a strong prime.
It is an emirp because it is prime and its reverse (7041242103131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313012421407 - 220 = 1313011372831 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1313012421407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313012421467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656506210703 + 656506210704.
It is an arithmetic number, because the mean of its divisors is an integer number (656506210704).
Almost surely, 21313012421407 is an apocalyptic number.
1313012421407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313012421407 is an equidigital number, since it uses as much as digits as its factorization.
1313012421407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 1313012421407 its reverse (7041242103131), we get a palindrome (8354254524538).
The spelling of 1313012421407 in words is "one trillion, three hundred thirteen billion, twelve million, four hundred twenty-one thousand, four hundred seven".
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