Base | Representation |
---|---|
bin | 11101110110101011111000… |
… | …100010011101010101001011 |
3 | 122012220021122202012202211121 |
4 | 131312223320202131111023 |
5 | 114202220100411140243 |
6 | 1143130554350140111 |
7 | 36441131053321624 |
oct | 3566537042352513 |
9 | 565807582182747 |
10 | 131301320021323 |
11 | 38922639151a31 |
12 | 128870aa4b1637 |
13 | 5835879ca761a |
14 | 245d036b9aa4b |
15 | 102a6ae3161ed |
hex | 776af889d54b |
131301320021323 has 2 divisors, whose sum is σ = 131301320021324. Its totient is φ = 131301320021322.
The previous prime is 131301320021293. The next prime is 131301320021327. The reversal of 131301320021323 is 323120023103131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131301320021323 is a prime.
It is not a weakly prime, because it can be changed into another prime (131301320021327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650660010661 + 65650660010662.
It is an arithmetic number, because the mean of its divisors is an integer number (65650660010662).
Almost surely, 2131301320021323 is an apocalyptic number.
131301320021323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131301320021323 is an equidigital number, since it uses as much as digits as its factorization.
131301320021323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 131301320021323 its reverse (323120023103131), we get a palindrome (454421343124454).
The spelling of 131301320021323 in words is "one hundred thirty-one trillion, three hundred one billion, three hundred twenty million, twenty-one thousand, three hundred twenty-three".
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