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13130141952437 is a prime number
BaseRepresentation
bin1011111100010001100101…
…1100100110100110110101
31201111020012011112201000222
42333010121130212212311
53210111012314434222
643531523130144125
72523423105060266
oct277043134464665
951436164481028
1013130141952437
114202509914894
121580861b82045
137432230a1b73
143357062c296d
1517b829bda542
hexbf1197269b5

13130141952437 has 2 divisors, whose sum is σ = 13130141952438. Its totient is φ = 13130141952436.

The previous prime is 13130141952427. The next prime is 13130141952463. The reversal of 13130141952437 is 73425914103131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11861452850116 + 1268689102321 = 3444046^2 + 1126361^2 .

It is an emirp because it is prime and its reverse (73425914103131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13130141952437 - 210 = 13130141951413 is a prime.

It is a super-2 number, since 2×131301419524372 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13130141952407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565070976218 + 6565070976219.

It is an arithmetic number, because the mean of its divisors is an integer number (6565070976219).

Almost surely, 213130141952437 is an apocalyptic number.

It is an amenable number.

13130141952437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130141952437 is an equidigital number, since it uses as much as digits as its factorization.

13130141952437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 272160, while the sum is 44.

The spelling of 13130141952437 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-one million, nine hundred fifty-two thousand, four hundred thirty-seven".