Base | Representation |
---|---|
bin | 1011111100010001111000… |
… | …1110011010110011100001 |
3 | 1201111020101202101122110221 |
4 | 2333010132032122303201 |
5 | 3210111143330321121 |
6 | 43531535112323041 |
7 | 2523425100352366 |
oct | 277043616326341 |
9 | 51436352348427 |
10 | 13130222120161 |
11 | 42025500a0003 |
12 | 15808849a3481 |
13 | 7432368906a3 |
14 | 335712bd046d |
15 | 17b831c73b41 |
hex | bf11e39ace1 |
13130222120161 has 2 divisors, whose sum is σ = 13130222120162. Its totient is φ = 13130222120160.
The previous prime is 13130222120009. The next prime is 13130222120201. The reversal of 13130222120161 is 16102122203131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12145922010000 + 984300110161 = 3485100^2 + 992119^2 .
It is a cyclic number.
It is not a de Polignac number, because 13130222120161 - 29 = 13130222119649 is a prime.
It is not a weakly prime, because it can be changed into another prime (13130222124161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565111060080 + 6565111060081.
It is an arithmetic number, because the mean of its divisors is an integer number (6565111060081).
Almost surely, 213130222120161 is an apocalyptic number.
It is an amenable number.
13130222120161 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130222120161 is an equidigital number, since it uses as much as digits as its factorization.
13130222120161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 13130222120161 its reverse (16102122203131), we get a palindrome (29232344323292).
The spelling of 13130222120161 in words is "thirteen trillion, one hundred thirty billion, two hundred twenty-two million, one hundred twenty thousand, one hundred sixty-one".
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