Base | Representation |
---|---|
bin | 10011000110110110010… |
… | …001101011011100100001 |
3 | 11122112010211122010202102 |
4 | 103012312101223130201 |
5 | 133003032404103433 |
6 | 2443110002100145 |
7 | 163601636212004 |
oct | 23066621533441 |
9 | 4575124563672 |
10 | 1313023112993 |
11 | 466939353799 |
12 | 19258094a655 |
13 | 96a821cc467 |
14 | 4779d00d53b |
15 | 2424c3e04e8 |
hex | 131b646b721 |
1313023112993 has 2 divisors, whose sum is σ = 1313023112994. Its totient is φ = 1313023112992.
The previous prime is 1313023112977. The next prime is 1313023113011. The reversal of 1313023112993 is 3992113203131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 896369645824 + 416653467169 = 946768^2 + 645487^2 .
It is an emirp because it is prime and its reverse (3992113203131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313023112993 - 24 = 1313023112977 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313023115993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656511556496 + 656511556497.
It is an arithmetic number, because the mean of its divisors is an integer number (656511556497).
Almost surely, 21313023112993 is an apocalyptic number.
It is an amenable number.
1313023112993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313023112993 is an equidigital number, since it uses as much as digits as its factorization.
1313023112993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 38.
The spelling of 1313023112993 in words is "one trillion, three hundred thirteen billion, twenty-three million, one hundred twelve thousand, nine hundred ninety-three".
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