Base | Representation |
---|---|
bin | 1011111100010001111101… |
… | …1111010101011100011111 |
3 | 1201111020110020022022110211 |
4 | 2333010133133111130133 |
5 | 3210111214243104441 |
6 | 43531541151113251 |
7 | 2523425445556201 |
oct | 277043737253437 |
9 | 51436406268424 |
10 | 13130243331871 |
11 | 4202561068746 |
12 | 158088bb12827 |
13 | 74323b0a94b3 |
14 | 335715952771 |
15 | 17b833a63a81 |
hex | bf11f7d571f |
13130243331871 has 2 divisors, whose sum is σ = 13130243331872. Its totient is φ = 13130243331870.
The previous prime is 13130243331851. The next prime is 13130243332039. The reversal of 13130243331871 is 17813334203131.
It is a weak prime.
It is an emirp because it is prime and its reverse (17813334203131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13130243331871 - 241 = 10931220076319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130243331851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565121665935 + 6565121665936.
It is an arithmetic number, because the mean of its divisors is an integer number (6565121665936).
Almost surely, 213130243331871 is an apocalyptic number.
13130243331871 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130243331871 is an equidigital number, since it uses as much as digits as its factorization.
13130243331871 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 40.
The spelling of 13130243331871 in words is "thirteen trillion, one hundred thirty billion, two hundred forty-three million, three hundred thirty-one thousand, eight hundred seventy-one".
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