Base | Representation |
---|---|
bin | 1011111100010010001000… |
… | …0011101101101101100111 |
3 | 1201111020120020101120020101 |
4 | 2333010202003231231213 |
5 | 3210111311311013022 |
6 | 43531545330444531 |
7 | 2523426511050034 |
oct | 277044203555547 |
9 | 51436506346211 |
10 | 13130286422887 |
11 | 420258341a657 |
12 | 15808a2433747 |
13 | 743246cb5c3a |
14 | 33571b56c38b |
15 | 17b837726627 |
hex | bf1220edb67 |
13130286422887 has 2 divisors, whose sum is σ = 13130286422888. Its totient is φ = 13130286422886.
The previous prime is 13130286422881. The next prime is 13130286422899. The reversal of 13130286422887 is 78822468203131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13130286422887 - 231 = 13128138939239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130286422881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565143211443 + 6565143211444.
It is an arithmetic number, because the mean of its divisors is an integer number (6565143211444).
Almost surely, 213130286422887 is an apocalyptic number.
13130286422887 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130286422887 is an equidigital number, since it uses as much as digits as its factorization.
13130286422887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6193152, while the sum is 55.
The spelling of 13130286422887 in words is "thirteen trillion, one hundred thirty billion, two hundred eighty-six million, four hundred twenty-two thousand, eight hundred eighty-seven".
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