Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …111100100010100011010011 |
3 | 122012220110022022222211002012 |
4 | 131312231203330202203103 |
5 | 114202232243214124223 |
6 | 1143131453241213135 |
7 | 36441223524134003 |
oct | 3566554374424323 |
9 | 565813268884065 |
10 | 131303122020563 |
11 | 389233833516a9 |
12 | 12887511a911ab |
13 | 5835aa641766c |
14 | 245d168234003 |
15 | 102a767616c78 |
hex | 776b63f228d3 |
131303122020563 has 2 divisors, whose sum is σ = 131303122020564. Its totient is φ = 131303122020562.
The previous prime is 131303122020547. The next prime is 131303122020613. The reversal of 131303122020563 is 365020221303131.
It is a weak prime.
It is an emirp because it is prime and its reverse (365020221303131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131303122020563 - 24 = 131303122020547 is a prime.
It is not a weakly prime, because it can be changed into another prime (131303122020523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651561010281 + 65651561010282.
It is an arithmetic number, because the mean of its divisors is an integer number (65651561010282).
Almost surely, 2131303122020563 is an apocalyptic number.
131303122020563 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303122020563 is an equidigital number, since it uses as much as digits as its factorization.
131303122020563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 131303122020563 its reverse (365020221303131), we get a palindrome (496323343323694).
The spelling of 131303122020563 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twenty-two million, twenty thousand, five hundred sixty-three".
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