Base | Representation |
---|---|
bin | 11101110110101101101010… |
… | …011100101001010110110111 |
3 | 122012220110120221020122102001 |
4 | 131312231222130221112313 |
5 | 114202233004130202333 |
6 | 1143131512135200131 |
7 | 36441226320243601 |
oct | 3566555234512667 |
9 | 565813527218361 |
10 | 131303231100343 |
11 | 38923429984985 |
12 | 12887542516047 |
13 | 5835ac2bb9c03 |
14 | 245d17890a171 |
15 | 102a771eb1b7d |
hex | 776b6a7295b7 |
131303231100343 has 2 divisors, whose sum is σ = 131303231100344. Its totient is φ = 131303231100342.
The previous prime is 131303231100299. The next prime is 131303231100359. The reversal of 131303231100343 is 343001132303131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131303231100343 - 213 = 131303231092151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303231100383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651615550171 + 65651615550172.
It is an arithmetic number, because the mean of its divisors is an integer number (65651615550172).
Almost surely, 2131303231100343 is an apocalyptic number.
131303231100343 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303231100343 is an equidigital number, since it uses as much as digits as its factorization.
131303231100343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 131303231100343 its reverse (343001132303131), we get a palindrome (474304363403474).
The spelling of 131303231100343 in words is "one hundred thirty-one trillion, three hundred three billion, two hundred thirty-one million, one hundred thousand, three hundred forty-three".
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