Base | Representation |
---|---|
bin | 1011111100010010010011… |
… | …0110100111010000001111 |
3 | 1201111020200111122012021011 |
4 | 2333010210312213100033 |
5 | 3210111410312221312 |
6 | 43531554123550051 |
7 | 2523430620502645 |
oct | 277044466472017 |
9 | 51436614565234 |
10 | 13130333320207 |
11 | 42025a7941274 |
12 | 15808b608b327 |
13 | 74325392602c |
14 | 335723899195 |
15 | 17b83b8dbda7 |
hex | bf124da740f |
13130333320207 has 2 divisors, whose sum is σ = 13130333320208. Its totient is φ = 13130333320206.
The previous prime is 13130333320189. The next prime is 13130333320213. The reversal of 13130333320207 is 70202333303131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13130333320207 - 231 = 13128185836559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130333321207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565166660103 + 6565166660104.
It is an arithmetic number, because the mean of its divisors is an integer number (6565166660104).
Almost surely, 213130333320207 is an apocalyptic number.
13130333320207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130333320207 is an equidigital number, since it uses as much as digits as its factorization.
13130333320207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20412, while the sum is 31.
Adding to 13130333320207 its reverse (70202333303131), we get a palindrome (83332666623338).
The spelling of 13130333320207 in words is "thirteen trillion, one hundred thirty billion, three hundred thirty-three million, three hundred twenty thousand, two hundred seven".
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