Base | Representation |
---|---|
bin | 1011111100010010101011… |
… | …0111001001100110111111 |
3 | 1201111020221112022120101020 |
4 | 2333010222313021212333 |
5 | 3210112112113433343 |
6 | 43532012124315223 |
7 | 2523433253354133 |
oct | 277045267114677 |
9 | 51436845276336 |
10 | 13130434124223 |
11 | 4202649831879 |
12 | 15809239a2b13 |
13 | 74326b78b790 |
14 | 3357330193c3 |
15 | 17b84569eb83 |
hex | bf12adc99bf |
13130434124223 has 32 divisors (see below), whose sum is σ = 18865827288000. Its totient is φ = 8075181327360.
The previous prime is 13130434124219. The next prime is 13130434124243. The reversal of 13130434124223 is 32242143403131.
It is not a de Polignac number, because 13130434124223 - 22 = 13130434124219 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130434124243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 530531653 + ... + 530556401.
It is an arithmetic number, because the mean of its divisors is an integer number (589557102750).
Almost surely, 213130434124223 is an apocalyptic number.
13130434124223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13130434124223 is a deficient number, since it is larger than the sum of its proper divisors (5735393163777).
13130434124223 is a wasteful number, since it uses less digits than its factorization.
13130434124223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32779.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13130434124223 its reverse (32242143403131), we get a palindrome (45372577527354).
The spelling of 13130434124223 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, one hundred twenty-four thousand, two hundred twenty-three".
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