Base | Representation |
---|---|
bin | 1011111100010011000000… |
… | …0110111010010111000111 |
3 | 1201111021011122221100021111 |
4 | 2333010300012322113013 |
5 | 3210112302132022101 |
6 | 43532024551025451 |
7 | 2523435402453151 |
oct | 277046006722707 |
9 | 51437148840244 |
10 | 13130522142151 |
11 | 4202694489a67 |
12 | 158094936b287 |
13 | 743283a984ab |
14 | 3357409abad1 |
15 | 17b84d289251 |
hex | bf1301ba5c7 |
13130522142151 has 2 divisors, whose sum is σ = 13130522142152. Its totient is φ = 13130522142150.
The previous prime is 13130522142137. The next prime is 13130522142187. The reversal of 13130522142151 is 15124122503131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13130522142151 is a prime.
It is a super-2 number, since 2×131305221421512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130522142131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565261071075 + 6565261071076.
It is an arithmetic number, because the mean of its divisors is an integer number (6565261071076).
Almost surely, 213130522142151 is an apocalyptic number.
13130522142151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130522142151 is an equidigital number, since it uses as much as digits as its factorization.
13130522142151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 13130522142151 its reverse (15124122503131), we get a palindrome (28254644645282).
The spelling of 13130522142151 in words is "thirteen trillion, one hundred thirty billion, five hundred twenty-two million, one hundred forty-two thousand, one hundred fifty-one".
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