Base | Representation |
---|---|
bin | 1011111100010011000000… |
… | …1010011001010100100111 |
3 | 1201111021011201122202000111 |
4 | 2333010300022121110213 |
5 | 3210112302400233044 |
6 | 43532025022353451 |
7 | 2523435413305531 |
oct | 277046012312447 |
9 | 51437151582014 |
10 | 13130523055399 |
11 | 4202694a53112 |
12 | 158094972b887 |
13 | 743284028089 |
14 | 335740b68851 |
15 | 17b84d3b9b34 |
hex | bf130299527 |
13130523055399 has 2 divisors, whose sum is σ = 13130523055400. Its totient is φ = 13130523055398.
The previous prime is 13130523055339. The next prime is 13130523055421. The reversal of 13130523055399 is 99355032503131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13130523055399 - 223 = 13130514666791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130523055339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565261527699 + 6565261527700.
It is an arithmetic number, because the mean of its divisors is an integer number (6565261527700).
Almost surely, 213130523055399 is an apocalyptic number.
13130523055399 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130523055399 is an equidigital number, since it uses as much as digits as its factorization.
13130523055399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1640250, while the sum is 49.
The spelling of 13130523055399 in words is "thirteen trillion, one hundred thirty billion, five hundred twenty-three million, fifty-five thousand, three hundred ninety-nine".
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