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1313094468253 is a prime number
BaseRepresentation
bin10011000110111010100…
…001111000001010011101
311122112022210220100202211
4103012322201320022131
5133003204140441003
62443121031320421
7163603463551561
oct23067241701235
94575283810684
101313094468253
1146697565aa87
121925a0820111
1396a93c23ac9
14477a86a56a1
15242537d796d
hex131ba87829d

1313094468253 has 2 divisors, whose sum is σ = 1313094468254. Its totient is φ = 1313094468252.

The previous prime is 1313094468193. The next prime is 1313094468281. The reversal of 1313094468253 is 3528644903131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1147870103769 + 165224364484 = 1071387^2 + 406478^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313094468253 - 213 = 1313094460061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313094468197 and 1313094468206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313094468053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656547234126 + 656547234127.

It is an arithmetic number, because the mean of its divisors is an integer number (656547234127).

Almost surely, 21313094468253 is an apocalyptic number.

It is an amenable number.

1313094468253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313094468253 is an equidigital number, since it uses as much as digits as its factorization.

1313094468253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1866240, while the sum is 49.

The spelling of 1313094468253 in words is "one trillion, three hundred thirteen billion, ninety-four million, four hundred sixty-eight thousand, two hundred fifty-three".