Base | Representation |
---|---|
bin | 10011000110111010100… |
… | …001111000001010011101 |
3 | 11122112022210220100202211 |
4 | 103012322201320022131 |
5 | 133003204140441003 |
6 | 2443121031320421 |
7 | 163603463551561 |
oct | 23067241701235 |
9 | 4575283810684 |
10 | 1313094468253 |
11 | 46697565aa87 |
12 | 1925a0820111 |
13 | 96a93c23ac9 |
14 | 477a86a56a1 |
15 | 242537d796d |
hex | 131ba87829d |
1313094468253 has 2 divisors, whose sum is σ = 1313094468254. Its totient is φ = 1313094468252.
The previous prime is 1313094468193. The next prime is 1313094468281. The reversal of 1313094468253 is 3528644903131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1147870103769 + 165224364484 = 1071387^2 + 406478^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313094468253 - 213 = 1313094460061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313094468197 and 1313094468206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313094468053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656547234126 + 656547234127.
It is an arithmetic number, because the mean of its divisors is an integer number (656547234127).
Almost surely, 21313094468253 is an apocalyptic number.
It is an amenable number.
1313094468253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313094468253 is an equidigital number, since it uses as much as digits as its factorization.
1313094468253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 49.
The spelling of 1313094468253 in words is "one trillion, three hundred thirteen billion, ninety-four million, four hundred sixty-eight thousand, two hundred fifty-three".
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