Base | Representation |
---|---|
bin | 11101110110110011111110… |
… | …101100101100000110111111 |
3 | 122012221010002121011010220202 |
4 | 131312303332230230012333 |
5 | 114202340401401114213 |
6 | 1143134553133234115 |
7 | 36441556353064103 |
oct | 3566637654540677 |
9 | 565833077133822 |
10 | 131310013301183 |
11 | 3892629a299842 |
12 | 1288891593293b |
13 | 58366340460c2 |
14 | 245d61d56d903 |
15 | 102aa1c607b58 |
hex | 776cfeb2c1bf |
131310013301183 has 2 divisors, whose sum is σ = 131310013301184. Its totient is φ = 131310013301182.
The previous prime is 131310013301171. The next prime is 131310013301213. The reversal of 131310013301183 is 381103310013131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131310013301183 - 228 = 131309744865727 is a prime.
It is a super-4 number, since 4×1313100133011834 (a number of 58 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131310013301113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655006650591 + 65655006650592.
It is an arithmetic number, because the mean of its divisors is an integer number (65655006650592).
Almost surely, 2131310013301183 is an apocalyptic number.
131310013301183 is a deficient number, since it is larger than the sum of its proper divisors (1).
131310013301183 is an equidigital number, since it uses as much as digits as its factorization.
131310013301183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 131310013301183 in words is "one hundred thirty-one trillion, three hundred ten billion, thirteen million, three hundred one thousand, one hundred eighty-three".
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