Base | Representation |
---|---|
bin | 10011000110111010110… |
… | …111101111110001011101 |
3 | 11122112100012200121200202 |
4 | 103012322313233301131 |
5 | 133003212122413203 |
6 | 2443121354233245 |
7 | 163603563356354 |
oct | 23067267576135 |
9 | 4575305617622 |
10 | 1313100201053 |
11 | 466978916133 |
12 | 1925a2725825 |
13 | 96a951802b4 |
14 | 477a935899b |
15 | 2425406b388 |
hex | 131badefc5d |
1313100201053 has 2 divisors, whose sum is σ = 1313100201054. Its totient is φ = 1313100201052.
The previous prime is 1313100201019. The next prime is 1313100201131. The reversal of 1313100201053 is 3501020013131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1094729041849 + 218371159204 = 1046293^2 + 467302^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313100201053 - 216 = 1313100135517 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313100203053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656550100526 + 656550100527.
It is an arithmetic number, because the mean of its divisors is an integer number (656550100527).
Almost surely, 21313100201053 is an apocalyptic number.
It is an amenable number.
1313100201053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313100201053 is an equidigital number, since it uses as much as digits as its factorization.
1313100201053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 1313100201053 its reverse (3501020013131), we get a palindrome (4814120214184).
The spelling of 1313100201053 in words is "one trillion, three hundred thirteen billion, one hundred million, two hundred one thousand, fifty-three".
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