13131022399777 has 2 divisors, whose sum is σ = 13131022399778. Its totient is φ = 13131022399776.

The previous prime is 13131022399771. The next prime is 13131022399783. The reversal of 13131022399777 is 77799322013131.

It is a balanced prime because it is at equal distance from previous prime (13131022399771) and next prime (13131022399783).

It can be written as a sum of positive squares in only one way, i.e., 12808675524241 + 322346875536 = 3578921^2 + 567756^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131022399777 is a prime.

It is a super-3 number, since 3×13131022399777³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13131022399771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565511199888 + 6565511199889.

It is an arithmetic number, because the mean of its divisors is an integer number (6565511199889).

Almost surely, 2^{13131022399777} is an apocalyptic number.

It is an amenable number.

13131022399777 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131022399777 is an equidigital number, since it uses as much as digits as its factorization.

13131022399777 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3000564, while the sum is 55.

The spelling of 13131022399777 in words is "thirteen trillion, one hundred thirty-one billion, twenty-two million, three hundred ninety-nine thousand, seven hundred seventy-seven".