13131022414333 has 2 divisors, whose sum is σ = 13131022414334. Its totient is φ = 13131022414332.

The previous prime is 13131022414319. The next prime is 13131022414337. The reversal of 13131022414333 is 33341422013131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8825783355684 + 4305239058649 = 2970822^2 + 2074907^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131022414333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13131022414295 and 13131022414304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131022414337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565511207166 + 6565511207167.

It is an arithmetic number, because the mean of its divisors is an integer number (6565511207167).

Almost surely, 2^{13131022414333} is an apocalyptic number.

It is an amenable number.

13131022414333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131022414333 is an equidigital number, since it uses as much as digits as its factorization.

13131022414333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13131022414333 its reverse (33341422013131), we get a palindrome (46472444427464).

The spelling of 13131022414333 in words is "thirteen trillion, one hundred thirty-one billion, twenty-two million, four hundred fourteen thousand, three hundred thirty-three".