Base | Representation |
---|---|
bin | 1011111100010100111100… |
… | …0111101010010011100110 |
3 | 1201111022111220221211002102 |
4 | 2333011033013222103212 |
5 | 3210114333330312410 |
6 | 43532152334412102 |
7 | 2523454321034642 |
oct | 277051707522346 |
9 | 51438456854072 |
10 | 13131042432230 |
11 | 4202931144668 |
12 | 1580a73661032 |
13 | 743337805a48 |
14 | 33578db25c22 |
15 | 17b87dcae2a5 |
hex | bf14f1ea4e6 |
13131042432230 has 16 divisors (see below), whose sum is σ = 23637589495200. Its totient is φ = 5252036280192.
The previous prime is 13131042432203. The next prime is 13131042432293. The reversal of 13131042432230 is 3223424013131.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13131042432193 and 13131042432202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47441699 + ... + 47717678.
It is an arithmetic number, because the mean of its divisors is an integer number (1477349343450).
Almost surely, 213131042432230 is an apocalyptic number.
13131042432230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13131042432230 is a deficient number, since it is larger than the sum of its proper divisors (10506547062970).
13131042432230 is a wasteful number, since it uses less digits than its factorization.
13131042432230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95173183.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13131042432230 its reverse (3223424013131), we get a palindrome (16354466445361).
The spelling of 13131042432230 in words is "thirteen trillion, one hundred thirty-one billion, forty-two million, four hundred thirty-two thousand, two hundred thirty".
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