131311011121033 has 2 divisors, whose sum is σ = 131311011121034. Its totient is φ = 131311011121032.

The previous prime is 131311011121027. The next prime is 131311011121181. The reversal of 131311011121033 is 330121110113131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113327372854089 + 17983638266944 = 10645533^2 + 4240712^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131311011121033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131311011120995 and 131311011121013.

It is not a weakly prime, because it can be changed into another prime (131311011121013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655505560516 + 65655505560517.

It is an arithmetic number, because the mean of its divisors is an integer number (65655505560517).

Almost surely, 2^{131311011121033} is an apocalyptic number.

It is an amenable number.

131311011121033 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311011121033 is an equidigital number, since it uses as much as digits as its factorization.

131311011121033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 131311011121033 its reverse (330121110113131), we get a palindrome (461432121234164).

The spelling of 131311011121033 in words is "one hundred thirty-one trillion, three hundred eleven billion, eleven million, one hundred twenty-one thousand, thirty-three".