131311011121181 has 2 divisors, whose sum is σ = 131311011121182. Its totient is φ = 131311011121180.

The previous prime is 131311011121033. The next prime is 131311011121183. The reversal of 131311011121181 is 181121110113131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117907760629156 + 13403250492025 = 10858534^2 + 3661045^2 .

It is an emirp because it is prime and its reverse (181121110113131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131311011121181 - 2⁴² = 126912964610077 is a prime.

It is a super-2 number, since 2×131311011121181² (a number of 29 digits) contains 22 as substring.

Together with 131311011121183, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131311011121181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131311011121183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655505560590 + 65655505560591.

It is an arithmetic number, because the mean of its divisors is an integer number (65655505560591).

Almost surely, 2^{131311011121181} is an apocalyptic number.

It is an amenable number.

131311011121181 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311011121181 is an equidigital number, since it uses as much as digits as its factorization.

131311011121181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 26.

The spelling of 131311011121181 in words is "one hundred thirty-one trillion, three hundred eleven billion, eleven million, one hundred twenty-one thousand, one hundred eighty-one".