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1313110301053 is a prime number
BaseRepresentation
bin10011000110111011011…
…110010001100101111101
311122112100220200202021211
4103012323132101211331
5133003222214113203
62443122354524421
7163604045253415
oct23067336214575
94575326622254
101313110301053
11466983594441
121925a5b96711
1396a972a8525
14477aa827645
1524254db3c6d
hex131bb79197d

1313110301053 has 2 divisors, whose sum is σ = 1313110301054. Its totient is φ = 1313110301052.

The previous prime is 1313110301047. The next prime is 1313110301131. The reversal of 1313110301053 is 3501030113131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1307370420409 + 5739880644 = 1143403^2 + 75762^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313110301053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313110301353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656555150526 + 656555150527.

It is an arithmetic number, because the mean of its divisors is an integer number (656555150527).

Almost surely, 21313110301053 is an apocalyptic number.

It is an amenable number.

1313110301053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313110301053 is an equidigital number, since it uses as much as digits as its factorization.

1313110301053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405, while the sum is 22.

Adding to 1313110301053 its reverse (3501030113131), we get a palindrome (4814140414184).

The spelling of 1313110301053 in words is "one trillion, three hundred thirteen billion, one hundred ten million, three hundred one thousand, fifty-three".