Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …100010101111011001001000 |
3 | 122012221012220102020202022120 |
4 | 131312310333202233121020 |
5 | 114202400113402242412 |
6 | 1143135253115051240 |
7 | 36441625333140324 |
oct | 3566647742573110 |
9 | 565835812222276 |
10 | 131311101212232 |
11 | 389267a83a7487 |
12 | 12888b7a140b20 |
13 | 5836778553456 |
14 | 245d6c3c42984 |
15 | 102aa82da1b8c |
hex | 776d3f8af648 |
131311101212232 has 32 divisors (see below), whose sum is σ = 328280429184000. Its totient is φ = 43770010250304.
The previous prime is 131311101212209. The next prime is 131311101212243. The reversal of 131311101212232 is 232212101113131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19287607 + ... + 25191942.
It is an arithmetic number, because the mean of its divisors is an integer number (10258763412000).
Almost surely, 2131311101212232 is an apocalyptic number.
131311101212232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131311101212232 is an abundant number, since it is smaller than the sum of its proper divisors (196969327971768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131311101212232 is a wasteful number, since it uses less digits than its factorization.
131311101212232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44602565 (or 44602561 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 131311101212232 its reverse (232212101113131), we get a palindrome (363523202325363).
The spelling of 131311101212232 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred one million, two hundred twelve thousand, two hundred thirty-two".
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