Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …101010011001101000100011 |
3 | 122012221012220120000202210221 |
4 | 131312310333222121220203 |
5 | 114202400114411022014 |
6 | 1143135253230103511 |
7 | 36441625356202534 |
oct | 3566647752315043 |
9 | 565835816022727 |
10 | 131311103220259 |
11 | 389267a9549106 |
12 | 12888b7a94ab97 |
13 | 5836778aa7431 |
14 | 245d6c420668b |
15 | 102aa8314bb24 |
hex | 776d3fa99a23 |
131311103220259 has 2 divisors, whose sum is σ = 131311103220260. Its totient is φ = 131311103220258.
The previous prime is 131311103220161. The next prime is 131311103220301. The reversal of 131311103220259 is 952022301113131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131311103220259 - 215 = 131311103187491 is a prime.
It is not a weakly prime, because it can be changed into another prime (131311103220859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655551610129 + 65655551610130.
It is an arithmetic number, because the mean of its divisors is an integer number (65655551610130).
Almost surely, 2131311103220259 is an apocalyptic number.
131311103220259 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311103220259 is an equidigital number, since it uses as much as digits as its factorization.
131311103220259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 34.
The spelling of 131311103220259 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred three million, two hundred twenty thousand, two hundred fifty-nine".
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