Base | Representation |
---|---|
bin | 11101110110110101000000… |
… | …110110101010011101110111 |
3 | 122012221012221221122110112101 |
4 | 131312311000312222131313 |
5 | 114202400140020242101 |
6 | 1143135255222402531 |
7 | 36441626021136121 |
oct | 3566650066523567 |
9 | 565835857573471 |
10 | 131311123212151 |
11 | 38926809863333 |
12 | 12888b85590447 |
13 | 583677cc86c5c |
14 | 245d6c6b2c211 |
15 | 102aa84c9a401 |
hex | 776d40daa777 |
131311123212151 has 2 divisors, whose sum is σ = 131311123212152. Its totient is φ = 131311123212150.
The previous prime is 131311123212083. The next prime is 131311123212169. The reversal of 131311123212151 is 151212321113131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131311123212151 - 223 = 131311114823543 is a prime.
It is a super-2 number, since 2×1313111232121512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131311123212751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655561606075 + 65655561606076.
It is an arithmetic number, because the mean of its divisors is an integer number (65655561606076).
Almost surely, 2131311123212151 is an apocalyptic number.
131311123212151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311123212151 is an equidigital number, since it uses as much as digits as its factorization.
131311123212151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1080, while the sum is 28.
Adding to 131311123212151 its reverse (151212321113131), we get a palindrome (282523444325282).
The spelling of 131311123212151 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred twenty-three million, two hundred twelve thousand, one hundred fifty-one".
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