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131311129163647 is a prime number
BaseRepresentation
bin11101110110110101000001…
…001101010111011101111111
3122012221012222100211211110011
4131312311001031113131333
5114202400143031214042
61143135255554124051
736441626122544326
oct3566650115273577
9565835870754404
10131311129163647
1138926812158824
1212888b87580627
13583678128bb54
14245d6c783b0bd
15102aa85573a17
hex776d4135777f

131311129163647 has 2 divisors, whose sum is σ = 131311129163648. Its totient is φ = 131311129163646.

The previous prime is 131311129163623. The next prime is 131311129163681. The reversal of 131311129163647 is 746361921113131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131311129163647 - 219 = 131311128639359 is a prime.

It is a super-2 number, since 2×1313111291636472 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131311129163647.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131311129160647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655564581823 + 65655564581824.

It is an arithmetic number, because the mean of its divisors is an integer number (65655564581824).

Almost surely, 2131311129163647 is an apocalyptic number.

131311129163647 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311129163647 is an equidigital number, since it uses as much as digits as its factorization.

131311129163647 is an evil number, because the sum of its binary digits is even.

The product of its digits is 489888, while the sum is 49.

The spelling of 131311129163647 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred twenty-nine million, one hundred sixty-three thousand, six hundred forty-seven".