131311130312489 has 2 divisors, whose sum is σ = 131311130312490. Its totient is φ = 131311130312488.

The previous prime is 131311130312429. The next prime is 131311130312491. The reversal of 131311130312489 is 984213031113131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129321360522025 + 1989769790464 = 11371955^2 + 1410592^2 .

It is an emirp because it is prime and its reverse (984213031113131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131311130312489 - 2³² = 131306835345193 is a prime.

It is a super-2 number, since 2×131311130312489² (a number of 29 digits) contains 22 as substring.

Together with 131311130312491, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131311130312429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655565156244 + 65655565156245.

It is an arithmetic number, because the mean of its divisors is an integer number (65655565156245).

Almost surely, 2^{131311130312489} is an apocalyptic number.

It is an amenable number.

131311130312489 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311130312489 is an equidigital number, since it uses as much as digits as its factorization.

131311130312489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 41.

The spelling of 131311130312489 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, three hundred twelve thousand, four hundred eighty-nine".