Base | Representation |
---|---|
bin | 11101110110110101000001… |
… | …010001110000000100100111 |
3 | 122012221012222110000020001202 |
4 | 131312311001101300010213 |
5 | 114202400143330003444 |
6 | 1143135300034513115 |
7 | 36441626135402240 |
oct | 3566650121600447 |
9 | 565835873006052 |
10 | 131311130312999 |
11 | 389268128732aa |
12 | 12888b87a3579b |
13 | 58367815a2040 |
14 | 245d6c7a59cc7 |
15 | 102aa856ee34e |
hex | 776d41470127 |
131311130312999 has 32 divisors (see below), whose sum is σ = 166746543774720. Its totient is φ = 100631295302400.
The previous prime is 131311130312959. The next prime is 131311130313031. The reversal of 131311130312999 is 999213031113131.
It is a cyclic number.
It is not a de Polignac number, because 131311130312999 - 28 = 131311130312743 is a prime.
It is a super-2 number, since 2×1313111303129992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131311130312909) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 126080747 + ... + 127117964.
It is an arithmetic number, because the mean of its divisors is an integer number (5210829492960).
Almost surely, 2131311130312999 is an apocalyptic number.
131311130312999 is a deficient number, since it is larger than the sum of its proper divisors (35435413461721).
131311130312999 is a wasteful number, since it uses less digits than its factorization.
131311130312999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253198911.
The product of its (nonzero) digits is 118098, while the sum is 47.
The spelling of 131311130312999 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, three hundred twelve thousand, nine hundred ninety-nine".
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