13131120131 has 2 divisors, whose sum is σ = 13131120132. Its totient is φ = 13131120130.

The previous prime is 13131120113. The next prime is 13131120133. The reversal of 13131120131 is 13102113131.

Together with previous prime (13131120113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13102113131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13131120131 - 2¹⁴ = 13131103747 is a prime.

It is a super-2 number, since 2×13131120131² (a number of 21 digits) contains 22 as substring.

Together with 13131120133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13131120133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565560065 + 6565560066.

It is an arithmetic number, because the mean of its divisors is an integer number (6565560066).

Almost surely, 2^13131120131 is an apocalyptic number.

13131120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131120131 is an equidigital number, since it uses as much as digits as its factorization.

13131120131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13131120131 its reverse (13102113131), we get a palindrome (26233233262).

The spelling of 13131120131 in words is "thirteen billion, one hundred thirty-one million, one hundred twenty thousand, one hundred thirty-one".