Base | Representation |
---|---|
bin | 1011111100010101010001… |
… | …0110111001001000101010 |
3 | 1201111022202001022112101110 |
4 | 2333011110112321020222 |
5 | 3210120023324424320 |
6 | 43532205154131150 |
7 | 2523456436014612 |
oct | 277052426711052 |
9 | 51438661275343 |
10 | 13131130311210 |
11 | 420297680741a |
12 | 1580a98b80ab6 |
13 | 74334ca94442 |
14 | 33579b67da42 |
15 | 17b88686c5e0 |
hex | bf1545b922a |
13131130311210 has 128 divisors (see below), whose sum is σ = 32050981186560. Its totient is φ = 3442567094784.
The previous prime is 13131130311197. The next prime is 13131130311227. The reversal of 13131130311210 is 1211303113131.
13131130311210 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1582631782 + ... + 1582640078.
It is an arithmetic number, because the mean of its divisors is an integer number (250398290520).
Almost surely, 213131130311210 is an apocalyptic number.
13131130311210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13131130311210 is an abundant number, since it is smaller than the sum of its proper divisors (18919850875350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13131130311210 is a wasteful number, since it uses less digits than its factorization.
13131130311210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12100.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 13131130311210 its reverse (1211303113131), we get a palindrome (14342433424341).
The spelling of 13131130311210 in words is "thirteen trillion, one hundred thirty-one billion, one hundred thirty million, three hundred eleven thousand, two hundred ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •