Base | Representation |
---|---|
bin | 11101110110110101010010… |
… | …100111110100010011111001 |
3 | 122012221020201201120102011220 |
4 | 131312311102213310103321 |
5 | 114202401242323411301 |
6 | 1143135344551542253 |
7 | 36441636301004466 |
oct | 3566652247642371 |
9 | 565836651512156 |
10 | 131311421310201 |
11 | 38926952058860 |
12 | 1288904938a989 |
13 | 58367c996a132 |
14 | 245d71456866d |
15 | 102aaa1030936 |
hex | 776d529f44f9 |
131311421310201 has 32 divisors (see below), whose sum is σ = 201252636902400. Its totient is φ = 75318496159680.
The previous prime is 131311421310187. The next prime is 131311421310221. The reversal of 131311421310201 is 102013124113131.
It is not a de Polignac number, because 131311421310201 - 217 = 131311421179129 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131311421310221) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 104404021 + ... + 105654258.
It is an arithmetic number, because the mean of its divisors is an integer number (6289144903200).
Almost surely, 2131311421310201 is an apocalyptic number.
131311421310201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131311421310201 is a deficient number, since it is larger than the sum of its proper divisors (69941215592199).
131311421310201 is a wasteful number, since it uses less digits than its factorization.
131311421310201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 210059309.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 131311421310201 its reverse (102013124113131), we get a palindrome (233324545423332).
The spelling of 131311421310201 in words is "one hundred thirty-one trillion, three hundred eleven billion, four hundred twenty-one million, three hundred ten thousand, two hundred one".
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