Base | Representation |
---|---|
bin | 1011111100010101100010… |
… | …0110000111100001110011 |
3 | 1201111022221000002210012221 |
4 | 2333011120212013201303 |
5 | 3210120200030124222 |
6 | 43532220214101511 |
7 | 2523461261242306 |
oct | 277053046074163 |
9 | 51438830083187 |
10 | 13131201411187 |
11 | 4202a02959932 |
12 | 1580ab894a897 |
13 | 743361729832 |
14 | 3357a6caab3d |
15 | 17b88cc140c7 |
hex | bf158987873 |
13131201411187 has 2 divisors, whose sum is σ = 13131201411188. Its totient is φ = 13131201411186.
The previous prime is 13131201411101. The next prime is 13131201411359. The reversal of 13131201411187 is 78111410213131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13131201411187 is a prime.
It is a super-3 number, since 3×131312014111873 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13131201411487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565600705593 + 6565600705594.
It is an arithmetic number, because the mean of its divisors is an integer number (6565600705594).
Almost surely, 213131201411187 is an apocalyptic number.
13131201411187 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131201411187 is an equidigital number, since it uses as much as digits as its factorization.
13131201411187 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 34.
The spelling of 13131201411187 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, four hundred eleven thousand, one hundred eighty-seven".
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