13131201419333 has 2 divisors, whose sum is σ = 13131201419334. Its totient is φ = 13131201419332.

The previous prime is 13131201419321. The next prime is 13131201419359. The reversal of 13131201419333 is 33391410213131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8388397290529 + 4742804128804 = 2896273^2 + 2177798^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131201419333 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13131201419293 and 13131201419302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131201419393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565600709666 + 6565600709667.

It is an arithmetic number, because the mean of its divisors is an integer number (6565600709667).

Almost surely, 2^{13131201419333} is an apocalyptic number.

It is an amenable number.

13131201419333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131201419333 is an equidigital number, since it uses as much as digits as its factorization.

13131201419333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 35.

The spelling of 13131201419333 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, four hundred nineteen thousand, three hundred thirty-three".